Nettet18. apr. 2024 · printf("%d %d %d",i, j, k); } main () { int i=10; f (i++,i++,i++); printf(" %d\n",i); i=10; f (i++,i++,i++); printf(" %d",i); } Output: Compiler specific question. Not all the compilers allow this. Explanation: This question … NettetThere are only two arguments to your printf call: "%d %d %d" and the result of evaluating (a,b,c). The result of (a,b,c) is just the last item in the list: c, which is 5. That's passed to printf, which displays 5 for the first %d.
{int a=-10,b=-3; printf("%d\n",-a++); printf("%d\ - 搜狗问问
Nettet13. nov. 2024 · 最佳答案本回答由达人推荐. 2024.11.14 回答. 首先需要了解的是++放在变量的前面和放在后面的作用. 放在前面的是先计算自增一操作. 放在后面的是先返回该变量的值,然后再计算自增一操作. 所以这里第一句就是输出-a的值,也就是10,输出后几点a=a+1,得到a=-9 ... Nettet7. jun. 2011 · 中文名称谷歌发布. 2006 年 4 月 12 日,Google 中文名称谷歌发布。. Google 行政总裁埃里克·施密特在北京与两位 Google 驻中国副总裁李开复、周韶宁共同发布了 Google 全球中文名称“谷歌”,意为“谷之歌”,也代表“播种之歌、期待之歌、收获之歌、喜悦 … most dangerous game 2020 watch online
单选题有以下程序:#include main(){ int c,d; c=10^3; d=10+3; …
Nettet25. nov. 2024 · 首先先说下原理: 1 printf函数对于括号内的表达式是从右向左执行,如 printf("%d,%d",b++,++b);先执行 ++b,再执行b++; 2对于++a和a++: ++a是先自加, … Nettet1. 2. 3. int a = 0; while ( ++a < 10 ) printf("%d\n", a); Which would print the numbers from 1 to 9. From your example it appears you are using the value of a inside your while loop. If this is true then you don't want to do the increment inside the while condition which is executed before the body of the loop. NettetIn your particular Example, printf evaluates a++ first, reads 10 and prints it and only then increments it to 11. printf then evaluates ++a, increments it first, reads 12 and prints it out. The last variable printf evaluates is read as it is (12) and is printed without any … most dangerous fruit to eat